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NEET NEET SOLVED PAPER 2016 Phase-II

  • question_answer
    An electron is moving in a circular path under the influence of a transverse magnetic field of\[3.57\times {{10}^{-2}}\] T. If the value of e/m is\[1.67\times {{10}^{11}}C/kg.\] the frequency of revolution of the electron is

    A)  1 GHz             

    B)  100 MHz

    C)  62.8 MHz                    

    D)  6.28 MHz

    Correct Answer: A

    Solution :

    \[f=\frac{qB}{2\pi m}=\frac{1.67\times {{10}^{11}}\times 3.57\times {{10}^{-2}}}{2\times 3.14}\] \[{{10}^{9}}HZ=1GHz\]


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