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NEET NEET SOLVED PAPER 2016 Phase-II

  • question_answer
    Photons with energy 5 eV are incident on a cathode C in a photoelectric cell. The maximum energy of emitted photoelectrons is 2 eV. When photons of energy 6 eV are incident on C, no photoelectrons will reach the anode A, if the stopping potential of A relative to C is

    A)  +3 V              

    B)  +4 V

    C)  -1 V                            

    D)  -3 V

    Correct Answer: D

    Solution :

    \[{{E}_{\max }}=E=\phi \] \[2eV=5eV-\phi \Rightarrow \phi =3eV\] \[Now\text{ }e{{V}_{0}}=E-\phi \] \[=6eV-3eV=3eV\] So stopping potential is -3V


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