A) 2.2 A
B) 11 A
C) 4.4 A
D) \[11\sqrt{2A}\]
Correct Answer: A
Solution :
\[R=100\Omega ,{{X}_{c}}=100\Omega \] \[{{I}_{\max }}=\frac{200V}{100}=\frac{200V}{100\Omega }=2.2A\]You need to login to perform this action.
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