A) 55 minutes
B) 110 minutes
C) 220 minutes
D) 330 minutes
Correct Answer: B
Solution :
For 1 mole\[C{{l}_{2}}\],2F electricity is required \[\therefore \]For 0.1 mole \[C{{l}_{2}}\] ,0.2F electricity will be required \[\therefore \] \[\therefore \,Q=I\times t\] Or, \[t=\frac{Q}{t}=\frac{0.2\times 96500}{3\times 60}\approx 110\,\min .\]
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