NEET NEET SOLVED PAPER 2017

  • question_answer
    Consider a drop of rain water having mass 1 g falling from a height of 1 km. It hits the ground with a speed of 50 m/s. Take g constant with a value\[10\,m/{{s}^{2}}.\]The work done by the (i) gravitational force and the (ii) resistive force of air is

    A)  (i) 10 J             (ii)  -8.75 J

    B)  (i)  -10 J           (ii) -8.25 J

    C)  (i) 1.25 J                               (ii) -8.25 J

    D)   (i) 100 J                               (ii) 8.75 J

    Correct Answer: A

    Solution :

    \[{{w}_{g}}{{w}_{a}}={{K}_{f}}-{{K}_{i}}\]                 \[mgh+{{w}_{a}}=\frac{1}{2}m{{v}^{2}}-0\] \[{{10}^{-3}}\times 10\times {{10}^{3}}+{{w}_{a}}=\frac{1}{2}\times {{10}^{-3}}\times {{(50)}^{2}}\] \[{{w}_{a}}=-8.75\,J\]i.e. work done due to air resistance and work done due to gravity = 10 J


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