A) 1800
B) 225
C) 450
D) 1000
Correct Answer: A
Solution :
Rate of power loss \[r\propto {{R}^{2}}{{T}^{4}}\] \[\frac{{{r}_{1}}}{{{r}_{2}}}=\frac{R_{1}^{2}T_{1}^{4}}{R_{2}^{2}T_{2}^{4}}\] \[=4\times \frac{1}{16}\] \[\frac{450}{{{r}_{2}}}=\frac{1}{4}\] \[{{r}_{2}}=1800\,\text{watt}\]
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