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NEET NEET SOLVED PAPER 2018

  • question_answer
    The volume (V) of a monatomic gas varies with its temperature (T), as shown in the graph. The ratio of work done by the gas, to the heat absorbed by it, when it undergoes a change from state A to state B, is [NEET - 2018]

    A)  \[\frac{1}{3}\]                                   

    B)  \[\frac{2}{3}\]

    C)  \[\frac{2}{5}\]                                   

    D)  \[\frac{2}{7}\]

    Correct Answer: C

    Solution :

    Given process is isobaric \[\text{dQ=n}{{\text{C}}_{\text{p}}}\text{dT}\] \[\text{dQ=n}\left( \frac{\text{5}}{\text{2}}\text{R} \right)\text{dT}\] \[\text{dW=PdV=nRdT}\] Required ratio\[\text{=}\frac{\text{dW}}{\text{dQ}}\text{=}\frac{\text{nRdT}}{\text{n}\left( \frac{\text{5}}{\text{2}}\text{R} \right)\text{dT}}\text{=}\frac{\text{2}}{\text{5}}\]


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