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NEET NEET SOLVED PAPER 2018

  • question_answer
    A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is \[20\text{ }m/{{s}^{2}}\]at a distance of 5 m from the mean position. The time period of oscillation is [NEET - 2018]

    A)  \[\text{2s}\]                            

    B)  \[\pi \text{s}\]

    C)  \[2\pi \text{s}\]                                   

    D)  \[1\text{s}\]

    Correct Answer: B

    Solution :

    \[\left| a \right|={{\omega }^{2}}y\] \[\Rightarrow 20={{\omega }^{2}}(5)\] \[\Rightarrow \omega =2rad/s\] \[T=\frac{2\pi }{\omega }=\frac{2\pi }{2}=\pi s\]


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