A) Benzoic acid
B) Acetanilide
C) Aniline
D) Glycine
Correct Answer: D
Solution :
\[\underset{\begin{smallmatrix} \downarrow \\ p{{K}_{a}}=9.60 \end{smallmatrix}}{\mathop{{{\text{H}}_{3}}\overset{\oplus }{\mathop{\text{N}}}\,}}\,\text{-C}{{\text{H}}_{2}}-\underset{\begin{smallmatrix} \downarrow \\ p{{K}_{a}}=2.34 \end{smallmatrix}}{\mathop{COOH}}\,\underset{(Zwitterion\,\,form)}{\mathop{{{H}_{3}}\overset{\oplus }{\mathop{N}}\,-C{{H}_{2}}-CO{{O}^{-}}}}\,\] \[{{\text{H}}_{\text{2}}}\text{N-C}{{\text{H}}_{\text{2}}}\text{-COO}\]
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