A) \[\text{C}{{\text{H}}_{\text{2}}}\text{=CH-CH=C}{{\text{H}}_{\text{2}}}\]
B) \[\text{C}{{\text{H}}_{\text{2}}}\text{=CH-C}\equiv \text{CH}\]
C) \[\text{HC}\equiv \text{C-C}\equiv \text{CH}\]
D) \[\text{C}{{\text{H}}_{\text{3}}}\text{-CH=CH-C}{{\text{H}}_{\text{3}}}\]
Correct Answer: B
Solution :
\[\overset{s{{p}^{2}}}{\mathop{\text{C}{{\text{H}}_{2}}}}\,=\overset{s{{p}^{2}}}{\mathop{CH}}\,-\overset{sp}{\mathop{C}}\,\equiv \overset{sp}{\mathop{CH}}\,\] Number of orbital require in hybridization = Number of \[\sigma -bonds\] around each carbon atom.
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