A) \[\frac{16F}{9}\]
B) \[\frac{4F}{3}\]
C) F
D) \[\frac{9F}{16}\]
Correct Answer: D
Solution :
\[F=\frac{KQQ}{{{r}^{2}}}\] \[F'=\frac{K\frac{3Q}{4}\times \frac{3Q}{4}}{{{r}^{2}}}=\frac{9F}{16}\]
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