A) t = 4.606/k
B) t = 2.303/k
C) t = 0.693/k
D) t = 6.909/k
Correct Answer: A
Solution :
Chemical kinetics \[t=\frac{2.3}{K}\log \frac{a}{a-x}\] \[=\frac{2.3}{k}\log \frac{1.0}{1}\] \[\frac{2.303\times 2}{k}\] \[{{t}_{99%}}=\frac{6.606}{k}4.606/k\]You need to login to perform this action.
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