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Punjab Medical Punjab - MET Solved Paper-1999

  • question_answer
    If the magnet of length \[10\,\,cm\] and pole strength \[40\,\,Am\] is placed at an angle of \[{{45}^{o}}\] in an uniform induction field of intensity \[2\times {{10}^{-4}}\]tesla. The couple acting on it will be

    A) \[0.656\times {{10}^{-5}}\,\,N\text{-}m\]

    B) \[0.656\times {{10}^{-4}}\,\,N\text{-}m\]

    C) \[0.5656\times {{10}^{-4}}\,\,N\text{-}m\]

    D) \[0.5656\times {{10}^{-3}}\,\,N\text{-}m\]

    Correct Answer: C

    Solution :

    Length of the magnet\[l=10\,\,cm\] \[m=40\,\,Am\] The strength\[m=40\,\,Am\] Angle\[\theta ={{45}^{o}}\] Induction\[B=2\times {{10}^{-4}}tesla\] Couple is\[\tau =mlB\sin \theta \] \[=40\times 0.1\times 2\times {{10}^{-4}}\sin {{45}^{o}}\] \[=8\times {{10}^{-4}}\times 0.707=0.5656\times {{10}^{-4}}N\text{-}m\]


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