Punjab Medical Punjab - MET Solved Paper-1999

  • question_answer
    Density of substance at \[{{0}^{o}}C\] is \[10\,\,g/cc\] and at\[{{100}^{o}}C\], its density is\[9.7\,\,g/cc\]. The coefficient of linear expansion of the substance will be

    A) \[{{10}^{2}}\]                                    

    B) \[{{10}^{-2}}\]

    C) \[{{10}^{-3}}\]                                  

    D) \[{{10}^{-4}}\]

    Correct Answer: D

    Solution :

    Initial temperature\[{{T}_{1}}={{0}^{o}}C\] Initial density\[{{\rho }_{1}}=10\,\,g/\sec \] Final temperature\[{{T}_{2}}={{100}^{o}}C\] Final density\[{{\rho }_{2}}=9.7\,\,g/cc\] coefficient of volumetric expression                 \[{{\alpha }_{v}}=\frac{\Delta \rho }{{{\rho }_{1}}\times \Delta T}=\frac{{{\rho }_{1}}-{{\rho }_{2}}}{\rho ({{T}_{1}}-{{T}_{2}})}\]                 \[=\frac{10-9.7}{10(100-0)}=\frac{0.3}{1000}=3\times {{10}^{-4}}\] Hence, coefficient of linear expansion is                 \[{{\alpha }_{l}}=\frac{{{\alpha }_{v}}}{3}=\frac{3\times {{10}^{-4}}}{3}={{10}^{-4}}{{/}^{o}}C\]


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