A) \[+2\]
B) \[+6\]
C) \[+4\]
D) \[+8\]
Correct Answer: B
Solution :
Let x be the oxidation number of chromium in\[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\]. Therefore,\[(2\times 1)+2x+7(-2)=0\]or\[2+2x-14=0\]or\[x=+6\]You need to login to perform this action.
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