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  3. Punjab Medical

Punjab Medical Punjab - MET Solved Paper-1999

  • question_answer
    The oxidation number of chromium in potassium dichromate \[({{K}_{2}}C{{r}_{2}}{{O}_{7}})\], is

    A) \[+2\]                                   

    B) \[+6\]

    C) \[+4\]                                   

    D) \[+8\]

    Correct Answer: B

    Solution :

    Let x be the oxidation number of chromium in\[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\]. Therefore,\[(2\times 1)+2x+7(-2)=0\]or\[2+2x-14=0\]or\[x=+6\]


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