Punjab Medical Punjab - MET Solved Paper-2001

  • question_answer
    If a cycle wheel of radius \[4\,\,m\] completes one revolution in two seconds. Then acceleration of the cycle will be

    A) \[{{\pi }^{2}}m/{{s}^{2}}\]                           

    B) \[2{{\pi }^{2}}m/{{s}^{2}}\]

    C) \[4{{\pi }^{2}}m/{{s}^{2}}\]                         

    D) \[8\pi \,\,m/{{s}^{2}}\]

    Correct Answer: C

    Solution :

    Here: Frequency of revolution\[t=\frac{1}{2}rev/\sec \] Radius of wheel of cycle\[r=4\,\,m\] The acceleration of the wheel is given by                 \[r={{\omega }^{2}}=r\times {{(2\pi \,\,f)}^{2}}=4\times {{\left( 2\times \pi \times \frac{1}{2} \right)}^{2}}\]


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