A) \[3.66\,\,m/{{s}^{2}}\]
B) \[5.66\,\,m/{{s}^{2}}\]
C) \[7.64\,\,m/{{s}^{2}}\]
D) \[9.66\,\,m/{{s}^{2}}\]
Correct Answer: D
Solution :
Here : depth\[(d)=100\,\,km={{10}^{5}}m\] Radius\[R=6380km=6.38\times {{10}^{6}}m\] Using the relation \[g=g\left( 1-\frac{d}{R} \right)=9.8\left( 1-\frac{{{10}^{5}}}{6.38\times {{10}^{6}}} \right)\] \[=\frac{9.8\times 62.8}{63.8}=9.65\,\,m/{{s}^{2}}\]
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