A) \[15\,\,\mu C\]
B) \[12\,\,\mu C\]
C) \[5\,\,\mu C\]
D) \[10\,\,\mu C\]
Correct Answer: D
Solution :
Equivalent capacitance is \[{{C}_{s}}\] given by when \[2\mu F\]and \[3\mu F\] and \[6\mu F\] capacitance are connected in series \[\frac{1}{{{C}_{s}}}=\frac{1}{2}+\frac{1}{3}+\frac{1}{6}=\frac{3+2+1}{6}=\frac{6}{6}=1\] So, \[{{C}_{s}}=1\mu F\]and\[V=10\,\,volt\] Using the relation \[Q=CV=1\times 10\mu C=10\,\,\mu C\]
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