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Punjab Medical Punjab - MET Solved Paper-2001

  • question_answer
    \[0.71\,\,g\]of chlorine combines with certain weight of a metal giving \[1.11\,\,g\] of its chloride. The equivalent weight of the metal is

    A) \[40\]                                   

    B) \[20\]

    C) \[80\]                                   

    D)  none

    Correct Answer: C

    Solution :

    Let metal chloride be\[MC{{l}_{n}}\]                 \[\therefore \]equivalents of metal                 = equivalents of chlorine or            \[\frac{1.11-0.71}{E}=\frac{0.71}{35.5}\]     \[\therefore \]      \[E=20\]


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