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Punjab Medical Punjab - MET Solved Paper-2001

  • question_answer
    A wheel of mass \[10\,\,kg\] has a moment of inertia of \[160\,\,kg\text{-}{{m}^{2}}\] about its own axis, the radius of gyration will be

    A) \[10\,\,m\]                        

    B) \[8\,\,m\]

    C) \[6\,\,m\]                                           

    D) \[4\,\,m\]

    Correct Answer: D

    Solution :

    Here: Mass of wheel\[M=10\,\,kg\] Moment of inertia\[160\,kg\,\,{{m}^{2}}\] (where \[K\] is radius of gyration) Using relation,\[I=M{{K}^{2}}\] \[160=10\times {{K}^{2}}\]or\[{{K}^{2}}=16\]or\[K=4\,\,m\]


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