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Punjab Medical Punjab - MET Solved Paper-2003

  • question_answer
    If the heat of \[110\,\,J\] is added to a gaseous system, whose internal energy is\[40\,\,J\], then the amount of external work done is:

    A) \[180\,\,\text{J}\]                           

    B) \[70\,\,\text{J}\]

    C) \[110\,\,\text{J}\]                           

    D) \[30\,\,\text{J}\]

    Correct Answer: B

    Solution :

    Heat added to the system\[\Delta Q=110\,\,\text{J}\] Internal energy\[\Delta U=40\,\,\text{J}\] External work done is given by                 \[\Delta W=\Delta Q-\Delta U=110-40\]                         \[=70\,\,\text{J}\]


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