A) \[4.8\times {{10}^{-19}}C,\,\,3\]
B) \[5.8\times {{10}^{-19}}C,\,\,4\]
C) \[3.8\times {{10}^{-19}}C,\,\,2\]
D) \[2.8\times {{10}^{-19}}C,\,\,1\]
Correct Answer: A
Solution :
Charge on the particle is given by \[qE=mg\] or \[q=\frac{mg}{E}\] \[=\frac{9.6\times {{10}^{-16}}\times 10}{20000}=4.8\times {{10}^{-19}}\] When there is an excess of \[n\] electrons on the particle, then \[q=ne\] So, \[n=\frac{q}{e}=\frac{4.8\times {{10}^{-19}}}{1.6\times {{10}^{-19}}}=3\]
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