A) \[7.625\times 10\,\,MeV\]
B) \[10.5\times {{10}^{29}}\,\,MeV\]
C) \[2.8\times {{10}^{-28}}\,\,MeV\]
D) \[5.625\times {{10}^{29}}\,\,MeV\]
Correct Answer: D
Solution :
According to Einsteins mass energy equivalence \[E=m{{c}^{2}}=1\times {{(3\times {{10}^{8}})}^{2}}\] \[=9\times {{10}^{16}}\,\,\text{J}\] \[=\frac{9\times {{10}^{16}}}{1.6\times {{10}^{-13}}}MeV\] (since\[1\,\,MeV=1.6\times {{10}^{-13}}J\]) \[=5.625\times {{10}^{29}}MeV\]
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