A) \[4\,\,\Omega ,\,\,8\,\,V\]
B) \[8\,\,\Omega ,\,\,4\,\,V\]
C) \[2\,\,\Omega ,\,\,2\,\,V\]
D) \[16\,\,\Omega ,\,\,8\,\,V\]
Correct Answer: A
Solution :
The equivalent resistance between \[A\] and \[B\] is \[\frac{1}{R}=\frac{1}{6}+\frac{1}{6}+\frac{1}{3}=\frac{2}{3}\] or \[R=\frac{3}{2}=1.5\Omega \] Now the equivalent resistance between \[A\] and \[B\] as \[R=1.5\Omega \] and \[2.5\Omega \] are connected in series, so \[R=1.5+2.5=4\,\,\Omega \] Now by ohms law, potential difference. Between \[A\] and \[B\] is given by \[{{V}_{A}}-{{V}_{B}}=iR=2\times 4.0\] \[=8\,\,volt\]
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