A) \[9.82\,\,kJ\]
B) \[89\,\,kJ\]
C) \[4.35\,\,kJ\]
D) \[5.17\,\,kJ\]
Correct Answer: D
Solution :
Here: weight of block\[w=2kN\], Distance\[d=10\,\,m\] Angle of inclination on the plane\[\alpha ={{15}^{o}}\] The block will be pulled up on a smooth Plane Hence, force of resistance due to inclination \[F=w\sin \alpha =2\times {{10}^{3}}\sin {{15}^{o}}\] \[=2\times {{10}^{3}}\times 0.2588\] \[=0.5176\,\,kN\] Now work done, \[W=Fd=0.5176\times {{10}^{3}}\times 10\] \[=5.17\,\,kN\]You need to login to perform this action.
You will be redirected in
3 sec