Punjab Medical Punjab - MET Solved Paper-2003

  • question_answer
    The earth of mass \[=6\times {{10}^{24}}kg\] revolves around the sun with an angular velocity of \[2\times {{10}^{-7}}\,\,rad/s\] in a circular orbit of radius\[1.5\times {{10}^{-8}}\,\,km\]. The force exerted by the sun on earth is:

    A) \[6\times {{10}^{19}}N\]                              

    B) \[18\times {{10}^{25}}N\]

    C) \[36\times {{10}^{21}}N\]                           

    D) \[27\times {{10}^{39}}N\]

    Correct Answer: C

    Solution :

    Here: mass of earth\[{{M}_{e}}=6\times {{10}^{24}}\,\,kg\] Angular velocity of earth                 \[\omega =2\times {{10}^{-7}}rad/s\] Radius of circular orbit                 \[R=1.5\times {{10}^{8}}km\]                    \[=1.5\times {{10}^{11}}m\] Force exerted on the earth by the sun is given by                 \[F={{M}_{e}}R{{\omega }^{2}}\]                     \[=6\times {{10}^{24}}\times 1.5\times {{10}^{11}}\times {{(2\times {{10}^{-7}})}^{2}}\]                     \[=36\times {{10}^{21}}N\]


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