Punjab Medical Punjab - MET Solved Paper-2004

  • question_answer
    The potential difference between the cathode and the target in a Coolidge tube is\[100\,\,kV\]. The minimum wavelength of the \[X-\]rays emitted by the tube is:

    A) \[0.66\,\,\overset{\text{o}}{\mathop{\text{A}}}\,\]                       

    B) \[9.38\,\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    C) \[0.246\,\,\overset{\text{o}}{\mathop{\text{A}}}\,\]                    

    D) \[0.123\,\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    Correct Answer: D

    Solution :

    Here: Potential difference\[V=100kV\]                 \[=100\times {{10}^{3}}V\] The minimum wavelength of the \[X-\]rays is                 \[{{\lambda }_{\min }}=\frac{hc}{eV}=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{1.6\times {{10}^{-19}}\times 100\times {{10}^{3}}}\]                         \[=0.123\times {{10}^{-10}}\]                         \[=0.123\overset{\text{o}}{\mathop{\text{A}}}\,\]


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