Punjab Medical Punjab - MET Solved Paper-2004

  • question_answer
    The volume occupied by one mole of water is [density of water\[=1\text{ }gm/c{{m}^{3}}:\]

    A) \[22400\,\,c{{m}^{3}}\]

    B) \[6.02\times {{10}^{-23}}c{{m}^{3}}\]

    C) \[3.0\times {{10}^{-23}}c{{m}^{3}}\]

    D) \[11200\,\,c{{m}^{3}}\]

    Correct Answer: C

    Solution :

    We know that volume occupied by one Molecule of water\[\text{=}\frac{\text{mass}\,\,\text{of}\,\,\text{water}}{\text{density}\,\,\text{of}\,\,\text{water}}\] mass of water\[=\frac{\text{molecular}\,\,\text{weight}}{6.02\times {{10}^{23}}}\]                                 \[=\frac{18}{6.02\times {{10}^{23}}}\]                                 \[=3.0\times {{10}^{-23}}\] \[\therefore \]  \[\text{volume}=\frac{3.0\times {{10}^{-23}}}{1}\]                                 \[=3.0\times {{10}^{-23}}\text{c}{{\text{m}}^{-3}}\]


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