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Punjab Medical Punjab - MET Solved Paper-2004

  • question_answer
    The molality of \[90%{{H}_{2}}S{{O}_{4}}\] solution is [density\[=1.8\,g\,\,ml\]]:

    A) \[1.8\]                                  

    B) \[48.4\]

    C) \[91.8\]                               

    D) \[94.6\]

    Correct Answer: C

    Solution :

    The density of solution\[=1.8\,g\,\,ml\] Weight of one litre of solution\[=1800\,\,g\] \[\therefore \]weight of \[{{H}_{2}}S{{O}_{4}}\] in the solution                 \[=\frac{1800\times 90}{100}\]                 \[=1620\,\,g\] \[\therefore \]weight of solvent\[=1800-1620\]                                       \[=180\,\,gm\] \[\therefore \]molality\[=\frac{1620}{98}\times \frac{100}{180}=91.8\]


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