Punjab Medical Punjab - MET Solved Paper-2004

  • question_answer
    An organic compound on analysis produce \[C=40%,\,\,H=13.33\]and\[N=46.67%\]. The empirical formula of this compound is

    A) \[C{{H}_{5}}N\]                

    B) \[C{{H}_{4}}N\]

    C) \[{{C}_{2}}{{H}_{5}}N\]                 

    D) \[{{C}_{2}}{{H}_{4}}N\]

    Correct Answer: B

    Solution :

    Element Percentage Relative no. of mol. Simple ratio of mol. Simplest whole number of ratio
    C 40 \[\frac{40}{12}=3.33\] \[\frac{3.33}{3.33}=1\] \[1\]
    H 13.33 \[\frac{13.33}{1}=13.33\] \[\frac{13.33}{3.33}=4\] \[4\]
    N 46.67 \[\frac{46.67}{14}=3.33\] \[\frac{3.33}{3.33}=1\] \[1\]
    Hence, the empirical formula\[=C{{H}_{4}}N\]


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