Punjab Medical Punjab - MET Solved Paper-2004

  • question_answer
    The weight of a residue obtained by heating \[2.76\,\,g\] of silver carbonate is:

    A) \[2.76\,\,g\]                      

    B) \[2.98\,\,g\]

    C) \[2.16\,\,g\]                      

    D) \[2.44\,\,g\]

    Correct Answer: C

    Solution :

    \[2A{{g}_{2}}+C{{O}_{3}}\xrightarrow{Heat}4Ag+2C{{O}_{2}}+{{O}_{2}}\] \[2[(2\times 108)+12+48]\]                         \[4\times 108\] \[2(216+12+48)\]                             \[4\times 108\] \[2\times 276=552\]                                       \[4\times 108=432\] \[\because \]\[552\,\,gm\]silver carbonate gives silver\[=432\,\,g\] \[\therefore \]\[2.76\,\,g\]silver carbonate gives                 \[\frac{432\times 2.76}{552}=2.16\,\,g\]


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