A) 2 times of \[H-\]mean value
B) 1/2 times of \[H\] mean value
C) 4 times of \[H\] mean value
D) same as \[H-\]mean value
Correct Answer: B
Solution :
\[\frac{{{{\bar{v}}}_{H}}}{{{{\bar{v}}}_{He}}}=\sqrt{\frac{{{M}_{{{H}_{e}}}}}{{{M}_{H}}}}=\sqrt{\left( \frac{4}{1} \right)}=\frac{2}{1}\]\[{{\bar{v}}_{He}}=\frac{1}{2}{{\bar{v}}_{H}}\]
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