A) \[400\sqrt{2}m/s\]
B) \[200\sqrt{2}m/s\]
C) \[400m/s\]
D) \[200m/s\]
Correct Answer: D
Solution :
Given: \[y=0.08\sin \frac{2\,\,\pi }{y}(200t-x)\] ? (1) Standard equation is given by \[y=a\sin \frac{2\,\,\pi }{\lambda }(vt-x)\] ... (2) On comparing eqs (1) and (2) \[v=200m/s\]
You need to login to perform this action.
You will be redirected in
3 sec
