A) \[16:1\]
B) \[18:1\]
C) \[4:1\]
D) \[2:1\]
Correct Answer: A
Solution :
Radius of orbit\[{{r}_{n}}\propto {{n}^{2}}\] For first excited state\[n=2\] and for ground state,\[n=1\] \[\therefore \] \[\frac{{{r}_{2}}}{{{r}_{1}}}={{\left( \frac{2}{1} \right)}^{2}}=\frac{4}{1}\] \[\therefore \]Ratio of areas \[={{\left( \frac{{{r}_{2}}}{{{r}_{1}}} \right)}^{2}}={{\left( \frac{4}{1} \right)}^{2}}=16:1\]
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