A) \[2.89\times {{10}^{-2}}{{T}^{-1}}\]
B) \[3.89\times {{10}^{-3}}{{T}^{-1}}\]
C) \[4.89\times {{10}^{-2}}{{T}^{-1}}\]
D) none of these
Correct Answer: A
Solution :
Let the initial amount of radioactive substance \[({{N}_{0}})\] be 100, then amount left after 48 days \[({{N}_{t}})=25\](given) Now, we know that disintegration constant \[K=\frac{2.303}{t}\log \frac{{{N}_{0}}}{{{N}_{t}}}\] Substituting the values \[K=\frac{2.303}{48}\log \frac{100}{25}\] \[K=0.0479\times \log 4=0.0479\times 0.6020\] \[K=0.0289{{T}^{-1}}\] \[=2.89\times {{10}^{-2}}{{T}^{-1}}\]
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