A) \[330%\]
B) \[225%\]
C) \[200%\]
D) \[300%\]
Correct Answer: D
Solution :
Momentum is given by \[p=\sqrt{2m\,\,{{E}_{k}}}\] or kinetic energy\[{{E}_{{{k}_{1}}}}=\frac{{{p}^{2}}}{2m}\] If momentum is increased by \[100%\] then new momentum\[=2p\] \[\therefore \]New kinetic energy will be \[{{E}_{{{k}_{2}}}}=\frac{{{(2p)}^{2}}}{2m}\] Percentage increase in kinetic energy is given by \[=\frac{{{E}_{{{k}_{2}}}}-{{E}_{{{k}_{1}}}}}{{{E}_{{{k}_{1}}}}}\times 100\] \[=300%\]
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