Punjab Medical Punjab - MET Solved Paper-2006

  • question_answer
    Pascal-second has the dimensions of:

    A)  force

    B)  energy

    C)  pressure

    D)  coefficient of viscosity

    Correct Answer: D

    Solution :

    From the formula of coefficient of viscosity we have                 \[\eta =\frac{F}{A(\Delta V/\Delta z)}\] where \[F\] is force, \[A\] is area,\[\frac{\Delta V}{\Delta z}\]is velocity gradient. \[\therefore \]Dimensions of \[\eta \] are\[\frac{[M{{L}^{-2}}]}{[{{L}^{2}}][L{{T}^{-1}}/L]}\]                                                 \[=[M{{L}^{-1}}{{T}^{-1}}]\] Pascal is unit of pressure, hence dimensional formula is\[[M{{L}^{-1}}{{T}^{-2}}]\] \[\therefore \]Dimensions of Pascal-second is\[[M{{L}^{-1}}{{T}^{-1}}]\] Hence, Pascal-second has dimensions of coefficient of viscosity.


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