A) \[\frac{3}{\sqrt{13}}\]
B) \[\frac{3}{\sqrt{26}}\]
C) \[\sqrt{\frac{3}{26}}\]
D) \[\sqrt{\frac{3}{13}}\]
Correct Answer: B
Solution :
\[|\mathbf{\vec{A}}|=\sqrt{{{(2)}^{2}}+{{(3)}^{2}}+{{(-1)}^{2}}}=\sqrt{4+9+1}=\sqrt{14}\] \[|\mathbf{\vec{B}}|=\sqrt{{{(-1)}^{2}}+{{3}^{2}}+{{4}^{2}}}=\sqrt{1+9+16}=\sqrt{26}\] \[\mathbf{\vec{A}}\cdot \mathbf{\vec{B}}=2(-1)+3\times 3+(-1)(4)=3\] The projection of\[\mathbf{\vec{A}}\]on\[\mathbf{\vec{B}}=\frac{\mathbf{\vec{A}}\cdot \mathbf{\vec{B}}}{|\mathbf{\vec{B}}|}=\frac{3}{\sqrt{26}}\]
You need to login to perform this action.
You will be redirected in
3 sec
