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Punjab Medical Punjab - MET Solved Paper-2007

  • question_answer
    Solution of \[0.1\,\,N\,\,N{{H}_{4}}OH\] and \[0.1\,\,N\,\,N{{H}_{4}}Cl\] has\[pH\,\,9.25\], then find out \[p{{K}_{b}}\]of\[N{{H}_{4}}OH\].

    A) \[9.25\]                               

    B) \[4.75\]

    C) \[3.75\]                               

    D) \[8.25\]

    Correct Answer: B

    Solution :

    Solution of \[N{{H}_{4}}OH\] and \[N{{H}_{4}}Cl\] acts as a basic buffer solution. For basic buffer solution,                 \[pOH=p{{K}_{b}}+\log \frac{[Salt]}{[Base]}\]                 \[pOH=14-pH=14-9.25=4.75\]                 \[4.75=p{{K}_{b}}+\log \frac{0.1}{0.1}\]                 \[p{{K}_{b}}=4.75\]


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