• question_answer Which reaction is not feasible? A) $2Kl+B{{r}_{2}}\to 3KBr+{{I}_{2}}$ B) $2KBr+{{I}_{2}}\to 2Kl+B{{r}_{2}}$ C) $2KBr+C{{l}_{2}}\to 2KCl+B{{r}_{2}}$ D) $2{{H}_{2}}O+2{{F}_{2}}\to 4HF+{{O}_{2}}$

$2KBr+{{I}_{2}}\xrightarrow{{}}2KI+B{{r}_{2}}$reaction is not possible because $B{{r}^{-}}$ ion is not oxidised in $B{{r}_{2}}$ with ${{I}_{2}}$ due to higher electrode potential of ${{I}_{2}}$ than bromine. In halogens fluorine can displace chlorine bromine and iodine, chlorine can displace bromine and iodine and bromide can displace iodine from their salts.