A) \[3.72\times {{10}^{-34}}J-s\]
B) \[2.11\times {{10}^{-34}}J-s\]
C) \[1.57\times {{10}^{-34}}J-s\]
D) \[1.11\times {{10}^{-34}}J-s\]
Correct Answer: B
Solution :
Energy of electron in nth energy level in hydrogen atom \[=-\frac{13.6}{{{n}^{2}}}eV\] Here, \[-\frac{13.6}{{{n}^{2}}}=-3.4eV\] So, \[n=2\] Angular momentum from Bohrs principle \[=n\,\,\frac{h}{2\pi }\] \[=\frac{2\times 6.626\times {{10}^{-34}}}{2\times 3.14}\] \[=2.11\times {{10}^{-34}}J\text{-}s\]
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