Punjab Medical Punjab - MET Solved Paper-2007

  • question_answer When\[C{{H}_{3}}C{{H}_{2}}CHC{{l}_{2}}\]is treated with\[NaN{{H}_{2}}\], the product formed is

    A) \[C{{H}_{3}}-CH=C{{H}_{2}}\]

    B) \[C{{H}_{3}}-CH\equiv CH\]

    C)

    D)

    Correct Answer: B

    Solution :

    \[C{{H}_{3}}-C{{H}_{2}}-CHC{{l}_{2}}\xrightarrow[\Delta ]{NaN{{H}_{2}}}\]\[C{{H}_{3}}-CH=CHCl\xrightarrow[\Delta ]{NaN{{H}_{2}}}\]\[C{{H}_{3}}-C\equiv CH\]

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