A) \[C{{H}_{3}}-CH=C{{H}_{2}}\]
B) \[C{{H}_{3}}-CH\equiv CH\]
C)
D)
Correct Answer: B
Solution :
\[C{{H}_{3}}-C{{H}_{2}}-CHC{{l}_{2}}\xrightarrow[\Delta ]{NaN{{H}_{2}}}\]\[C{{H}_{3}}-CH=CHCl\xrightarrow[\Delta ]{NaN{{H}_{2}}}\]\[C{{H}_{3}}-C\equiv CH\]
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