A) \[2:3\]
B) \[2:5\]
C) \[3:2\]
D) \[5:2\]
Correct Answer: C
Solution :
Thermal stress \[=Y\times \] strain or \[S=Y\varepsilon \] or \[S=Y\,\,\alpha \,\,t\] where \[\alpha =\]linear thermal expansion \[Y=\] Youngs modulus Here, \[{{S}_{1}}={{S}_{2}}\] \[\Rightarrow \] \[{{Y}_{1}}{{\alpha }_{1}}t={{Y}_{2}}{{\alpha }_{2}}t\] or \[\frac{{{Y}_{1}}}{{{Y}_{2}}}=\frac{{{\alpha }_{2}}}{{{\alpha }_{1}}}=\frac{3}{2}\] Thus, \[{{Y}_{1}}:{{Y}_{2}}=3:2\]You need to login to perform this action.
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