• # question_answer The equivalent capacity between the points$X$and$Y$in the circuit with$C=1\mu F$is A) $2\mu F$                          B) $3\mu F$ C) $1\mu F$                                          D) $0.5\mu F$

The circuit is shown in the figure. As points$a$and $b$ are at same potential, so no charge flows through$ab$. Now two remaining capacitors are in parallel, hence                 ${{C}_{eq}}=C+C=2C$                        $=2\times 1=2\mu F$