A) 10.3 s/day
B) 20.6 s/day
C) 5 s/day
D) 20 min/day
Correct Answer: A
Solution :
\[T=2\pi \sqrt{\frac{I}{g}}\] \[\frac{\Delta T}{T}=\frac{1}{2}\frac{\Delta l}{l}=\frac{1}{2}\alpha \,\,\Delta \theta \] \[=\frac{1}{2}\times 62\times {{10}^{-6}}(40-20)=12\times {{10}^{-5}}\] \[\Delta T=T\times 12\times {{10}^{-5}}\] \[=24\times 60\times 12\times {{10}^{-5}}\] \[=10.3s/day\]
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