A) 1
B) 2
C) 3
D) 4
Correct Answer: D
Solution :
When\[AgN{{O}_{3}}\]is added to\[CoC{{l}_{3}}\cdot xN{{H}_{3}}\]one mole of \[AgCl\] is formed hence, the value of\[x\]is 4. \[[Co{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]Cl{{[Co{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]}^{+}}\] \[+\underset{\begin{smallmatrix} can\,\,be \\ percipitated \end{smallmatrix}}{\mathop{C{{l}^{-}}}}\,\]You need to login to perform this action.
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