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Punjab Medical Punjab - MET Solved Paper-2008

  • question_answer
    A \[0.5g/L\] solution of glucose is found to be isotonic with a \[2.5g/L\] solution of an organic compound. What will be the molecular weight of that organic compound?

    A)  300                                       

    B)  600

    C)  900                                       

    D)  200

    Correct Answer: C

    Solution :

    Molarity of glucose solution\[=\frac{0.5g}{180\times 1L}=0.00278\,\,M\] Isotonic solution have equal molar concentrations, hence molarity of organic compound solution\[=0.00278M\] \[\therefore \]Molecular weight of compound\[=\frac{0.5g}{0.00278\times 1}=900\]


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