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Punjab Medical Punjab - MET Solved Paper-2009

  • question_answer
    At ordinary temperature, the molecules of an ideal gas have only translational and rotational kinetic energies. At high temperatures they may also have vibrational energy. As a result of this at higher temperatures (\[{{C}_{V}}=\]molar heat capacity at constant volume)

    A) \[{{C}_{V}}=\frac{3}{2}R\]for a monoatomic gas

    B) \[{{C}_{V}}>\frac{3}{2}R\]for a monoatomic gas

    C) \[{{C}_{V}}<\frac{5}{2}R\]for a diatomic gas

    D) \[{{C}_{V}}=\frac{5}{2}R\]for a diatomic gas

    Correct Answer: A

    Solution :

    At ordinary temperature, the vibrational kinetic energy of a monoatomic gas is zero. So,          \[{{C}_{V}}=\frac{3}{2}R\] The value is same for high temperature also. In case of diatomic gas   \[{{C}_{V}}=\frac{5}{2}R\](at low temperature) Also, \[{{C}_{V}}>\frac{5}{2}R\](at high temperature due to  vibrational kinetic energy)


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