Punjab Medical Punjab - MET Solved Paper-2009

  • question_answer
    A lump of clay of mass \[10g\] travelling with a velocity of \[10\,\,cm{{s}^{-1}}\] towards east collides head on with another lump of clay of mass\[10g\]travelling with velocity of\[20\,\,cm{{s}^{-1}}\]towards west. If the two lumps coalesce after collision, what is its velocity, if no external force acts on the system?

    A) \[15\,cm{{s}^{-1}}\]towards west

    B) \[15\,cm{{s}^{-1}}\]towards east

    C) \[5\,cm{{s}^{-1}}\]towards west

    D) \[5\,cm{{s}^{-1}}\]towards east

    Correct Answer: C

    Solution :

    Let velocity towards east be positive, then velocity towards west is negative. If \[v\] is the velocity of two lumps which are coalesced after collision, then from law of conservation of linear momentum                 \[{{m}_{1}}{{v}_{1}}+{{m}_{2}}{{v}_{2}}=({{m}_{1}}+{{m}_{2}})v\]                 \[10\times 20-10\times 10=20\times v\] \[\Rightarrow \]               \[v=\frac{100}{200}=5cm{{s}^{-1}}\] Hence, \[5cm{{s}^{-1}}\] towards west.


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